题目:
题解:
#include<iostream>
#include<string>
using namespace std;
int main()
{
string a;
int b;
cin >> a >> b;
int jin=0, xian=0; //上一位的进位和现位
//如果字符串只有一位
if(a.size()==1)
{
cout<<(a[0]-'0')/b<<' '<<(a[0]-'0')%b;
return 0;
}
for (int i = 0; i < (int)a.size(); i++)
{
xian = jin*10 + (a[i] - '0');
if (!(i == 0 && xian / b == 0))
{
cout << xian / b;
}
jin = xian % b;
}
cout << ' ' << jin;
return 0;
}