1883. 准时抵达会议现场的最小跳过休息次数

1883. 准时抵达会议现场的最小跳过休息次数

题目链接：1883. 准时抵达会议现场的最小跳过休息次数

代码如下：

//参考：https://leetcode.cn/problems/minimum-skips-to-arrive-at-meeting-on-time/solutions/2746611/jiao-ni-yi-bu-bu-si-kao-dong-tai-gui-hua-gxd2
class Solution {
public:
    int minSkips(vector<int>& dist, int speed, int hoursBefore) 
    {
        if(accumulate(dist.begin(),dist.end(),0)>(long long)speed*hoursBefore)
        {
            return -1;
        }
        int n=dist.size();
        vector<vector<int>> memo(n,vector<int>(n,-1));//-1代表没计算过
        function<int(int,int)> dfs=[&](int i,int j)->int
        {
            if(j<0)//递归边界
            {
                return 0;
            }
            auto &res=memo[i][j];
            if(res!=-1) return res;
            res=(dfs(i,j-1)+dist[j]+speed-1)/speed*speed;
            if(i) res=min(res,dfs(i-1,j-1)+dist[j]);
            return res;
        }; 
        for(int i=0;;i++)
        {
            if(dfs(i,n-2)+dist[n-1]<=(long long)speed*hoursBefore)
                return i;
        }
    }
};