(C++二叉树06) 二叉搜索树的最小绝对查和众数 二叉树的最近公共祖先

530、二叉搜索树的最小绝对差

递归法:

class Solution {
public:
    vector<int> vec;
    void traversal(TreeNode* root) {
        if(root == NULL) return;
        traversal(root->left);
        vec.push_back(root->val);
        traversal(root->right);
    }
    int getMinimumDifference(TreeNode* root) {
        traversal(root);
        if(vec.size() < 2) return 0;
        int res = INT_MAX;
        for(int i = 0; i < vec.size()-1; i++) {
            int dif = vec[i+1] - vec[i];
            if(dif < res) {
                res = dif;
            }
        }
        return res;
    }
};

迭代法:

class Solution {
public:
    int getMinimumDifference(TreeNode* root) {
        if(root == NULL) return 0;
        vector<int> vec;
        stack<TreeNode*> sta; 
        TreeNode* cur = root;
        while(cur != NULL || !sta.empty()) {
            while(cur != NULL) {
                sta.push(cur);
                cur = cur->left;
            }
            cur = sta.top();
            sta.pop();
            vec.push_back(cur->val);
            cur = cur->right;
        }
        if(vec.size() < 2) return 0;
        int res = INT_MAX;
        for(int i = 0; i < vec.size()-1; i++) {
            int dif = vec[i+1] - vec[i];
            if(dif < res) {
                res = dif;
            }
        }
        return res;
    }
};

501、二叉搜索树中的众数

递归法:

class Solution {
public:
    int maxCount = 0;
    int count = 0;
    vector<int> vec;
    TreeNode* pre = NULL;
    void traversal(TreeNode* root) {
        if(root == NULL) return;
        traversal(root->left);

        if(pre != NULL && pre->val == root->val) {
            count++;
        }else {
            count = 1;
        }
        pre = root;
        if(count == maxCount) {
            vec.push_back(pre->val);
        }else if(count > maxCount) {
            vec.clear();
            vec.push_back(pre->val);
            maxCount = count;
        }

        traversal(root->right);
    }
    vector<int> findMode(TreeNode* root) {
        if(root == NULL) return vec;
        traversal(root);
        return vec;
    }
};

236、二叉树的最近公共祖先

class Solution {
public:
    TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
        if(root == p || root == q || root == NULL) return root;
        TreeNode* left = lowestCommonAncestor(root->left, p, q);
        TreeNode* right = lowestCommonAncestor(root->right, p, q);

        if(left != NULL && right != NULL) return root;
        if(left == NULL && right != NULL) return right;
        if(left != NULL && right == NULL) return left;

        return NULL;
    }
};

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