【CodinGame】CLASH OF CODE - 20240715_2

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

a, b = [int(i) for i in input().split()]

answer = str()
answer += str(a-b)
answer += str(a+b)

print(answer)

import sys
import math

# Auto-generated code below aims at helping you parse
s = input()

mydic = {}
mydic["Scissors"] = "Stone"
mydic["Stone"] = "Hand"
mydic["Hand"] = "Scissors"

print(mydic.get(s,"Error"))

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

n = int(input())

for i in range(1,n+1,2):
    print(i)

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

a,b = map(int,input().split())

print(180-a-b)

a = int(input())
b= int(input())
c = int(input())

print((a+b)*c/2)

x = int(input())

print(x+x//2)

s = input()

print(s.count('A'),s.count('C'),s.count('G'),s.count('T'),end='')

n = int(input())

mystr = input()

print(mystr.replace(" ", ""))

x = int(input())
y = int(input())

for i in range(x):
    for j in range(y):
        print("O", end="")
    print()

或者（作者：Sberu）
for i in range(h):
    print('O'*w)

n = int(input())
ascii = list(map(int, input().split()))
# print(ascii)
# 对里面每一个数字转化为ascii码
for i in ascii:
    print(chr(i), end="")

mystr = input().split()
# 字符串逆序后输出字符串
print(' '.join(mystr[::-1]))

END