LeetCode 322. 零钱兑换
链接
class Solution {
public:
int coinChange(vector<int>& coins, int amount) {
if(amount == 0) {
return 0;
}
vector<int> dp(amount + 1, 0);
for(auto i : coins) {
if(i <= amount) {
dp[i] = 1;
}
}
for(int i = 0; i < coins.size(); i++) {
for(int j = 0; j <= amount; j++) {
if(j >= coins[i] && dp[j-coins[i]] != 0) {
if(dp[j] == 0) {
dp[j] = dp[j - coins[i]] + 1;
} else {
dp[j] = min(dp[j], dp[j - coins[i]] + 1);
}
}
}
}
if(dp[amount] == 0) {
return -1;
}
return dp[amount];
}
};
LeetCode 279. 完全平方数
链接
class Solution {
public:
int numSquares(int n) {
vector<int> dp(n + 1, INT_MAX);
dp[0] = 0;
for(int i = 1; i <= sqrt(n); i++) {
for(int j = i * i; j <= n; j++) {
dp[j] = min(dp[j], dp[j - i * i] + 1);
}
}
return dp[n];
}
};
LeetCode 139. 单词拆分
链接
class Solution {
public:
bool wordBreak(string s, vector<string>& wordDict) {
unordered_set<string> wordSet(wordDict.begin(), wordDict.end());
vector<bool> dp(s.size() + 1, false);
dp[0] = true;
for(int i = 1; i <= s.size(); i++) {
for(int j = 0; j < i; j++) {
string word = s.substr(j, i - j);
if(wordSet.find(word) != wordSet.end() && dp[j]) {
dp[i] = true;
}
}
}
return dp[s.size()];
}
};