【LC刷题】DAY02:24 19 142
24. 两两交换链表中的节点 link
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
ListNode* dummyHead = new ListNode(0);
dummyHead->next = head;
ListNode* temp = dummyHead;
while(temp->next!=nullptr && temp->next->next != nullptr){
ListNode *node1 = temp->next;
ListNode *node2 = node1->next;
temp->next = node2;
node1->next = node2->next;
node2 -> next = node1;
temp = node1;
}
return dummyHead->next;
}
};
19.删除链表的倒数第N个节点 link
class Solution {
public:
int getLength(ListNode* head) {
int length = 0;
while (head) {
++length;
head = head->next;
}
return length;
}
ListNode* removeNthFromEnd(ListNode* head, int n) {
ListNode* dummy = new ListNode(0, head);
int length = getLength(head);
ListNode* cur = dummy;
for (int i = 1; i < length - n + 1; ++i) {
cur = cur->next;
}
cur->next = cur->next->next;
ListNode* ans = dummy->next;
delete dummy;
return ans;
}
};
面试题 02.07. 链表相交 link
class Solution {
public:
ListNode *getIntersectionNode(ListNode *headA, ListNode *headB) {
unordered_set<ListNode *> visited;
ListNode *temp = headA;
while (temp != nullptr) {
visited.insert(temp);
temp = temp->next;
}
temp = headB;
while (temp != nullptr) {
if (visited.count(temp)) {
return temp;
}
temp = temp->next;
}
return nullptr;
}
};
142.环形链表II
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *detectCycle(ListNode *head) {
if (head == NULL)
return NULL;
ListNode *fast, *slow;
fast = head;
slow = head->next;
if(fast == slow){
return head;
}
while(fast->next!=NULL){
fast=fast->next;
slow = head;
while(slow != fast || slow == fast->next ){
if(fast->next == slow){
return slow;
}
slow=slow->next;
}
}
return NULL;
}
};