LeetCode //C - 605. Can Place Flowers

605. Can Place Flowers

You have a long flowerbed in which some of the plots are planted, and some are not. However, flowers cannot be planted in adjacent plots.

Given an integer array flowerbed containing 0’s and 1’s, where 0 means empty and 1 means not empty, and an integer n, return true if n new flowers can be planted in the flowerbed without violating the no-adjacent-flowers rule and false otherwise.
 

Example 1:

Input: flowerbed = [1,0,0,0,1], n = 1
Output: true

Example 2:

Input: flowerbed = [1,0,0,0,1], n = 2
Output: false

Constraints:

• $1<=flowerbed.length<=2\ast 10^4$
• flowerbed[i] is 0 or 1.
• There are no two adjacent flowers in flowerbed.
• 0 <= n <= flowerbed.length

From: LeetCode
Link: 605. Can Place Flowers

Solution:

Ideas：

• We iterate over each plot in the flowerbed.
• We check if the current plot is empty and its adjacent plots are also empty (or the plot is at the boundary of the flowerbed).
• If we can plant a flower, we set flowerbed[i] to 1 and decrement n.
• After the loop, we check if n has reached 0, indicating that all required flowers have been planted.

Code:

bool canPlaceFlowers(int* flowerbed, int flowerbedSize, int n) {
   
    for (int i = 0; i < flowerbedSize && n > 0; i++) {
   
        // Check if current plot is empty and adjacent plots are also empty (or non-existent)
        if (flowerbed[i] == 0) {
   
            bool emptyLeft = (i == 0) || (flowerbed[i - 1] == 0);
            bool emptyRight = (i == flowerbedSize - 1) || (flowerbed[i + 1] == 0);

            if (emptyLeft && emptyRight) {
   
                flowerbed[i] = 1; // Plant a flower
                n--; // Decrease the number of flowers needed
            }
        }
    }
    return n == 0; // Return true if all flowers can be planted, otherwise false
}