相邻的波峰减去相邻的波谷

def find_peak_trough_differences(nums):
    # 边界检查
    if len(nums) < 3:
        return []

    differences = []

    # 遍历列表以找到峰值并计算差值
    for i in range(1, len(nums) - 1):
        # 检查当前元素是否为峰值
        if nums[i] > nums[i - 1] and nums[i] > nums[i + 1]:
            # 查找左侧谷值
            left_trough = nums[i - 1]
            for j in range(i - 1, -1, -1):
                if j != 0:
                    if nums[j] < nums[j + 1] and nums[j]<nums[j-1] :
                        left_trough = nums[j]
                        break
                else:
                        left_trough = nums[0]
                    # 查找右侧谷值
            right_trough = nums[i + 1]
            for k in range(i+1, len(nums)):
                if k!=len(nums)-1:
                    if nums[k] < nums[k - 1] and nums[k]<nums[k+1]:
                        right_trough = nums[k]
                        break
                else:
                        right_trough = nums[-1]
                    # 计算差值并添加到列表中
            differences.append(nums[i] - left_trough)
            differences.append(nums[i] - right_trough)

    return differences


# 测试代码
nums = [1, 3, 5, 4, 2, 8, 10, 9, 7, 6]

# nums = [10,7,6,5,8,9,12,6,7,8,13,2,1]
print(find_peak_trough_differences(nums))

结果为5-1，5-2，10-2，10-6