使用场景：在做上课记录系统的时候，有上课开始时间和上课结束时间，需要计算这两个时间的插值，以分钟为单位。
封装方法如下：
from datetime import datetime
def sub_seconds(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
date1 = datetime.strptime(date1, "%Y-%m-%d %H:%M:%S")
date2 = datetime.strptime(date2, "%Y-%m-%d %H:%M:%S")
duration = date1 - date2
return duration.seconds
def sub_minute(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
return sub_seconds(date1, date2) / 60
def sub_hour(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
return sub_minute(date1, date2) / 60
def sub_day(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
return sub_hour(date1, date2) / 60
经过实测，不能使用duration.seconds，而是要改成duration.total_seconds()
def sub_seconds(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
date1 = datetime.strptime(date1, "%Y-%m-%d %H:%M:%S")
date2 = datetime.strptime(date2, "%Y-%m-%d %H:%M:%S")
duration = date1 - date2
return duration.total_seconds()
最终代码封装如下：
from datetime import datetime, timedelta
def sub_duration(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> timedelta:
date1 = datetime.strptime(date1, "%Y-%m-%d %H:%M:%S")
date2 = datetime.strptime(date2, "%Y-%m-%d %H:%M:%S")
return date1 - date2
def sub_seconds(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
duration = sub_duration(date1, date2)
return duration.total_seconds()
def sub_minutes(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
duration = sub_duration(date1, date2)
return duration.total_seconds() / 60
def sub_hours(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
duration = sub_duration(date1, date2)
return duration.total_seconds() / 3600
def sub_days(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
duration = sub_duration(date1, date2)
return duration.days
def sub_months(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
duration = sub_duration(date1, date2)
return duration.days / 30
def sub_years(
date1: str = "2024-07-11 12:33:33",
date2: str = "2024-07-10 12:33:33",
) -> float:
duration = sub_duration(date1, date2)
return duration.days / 365
测试代码如下：
import unittest
from datetime import datetime
import ztime
class TestCalcSub(unittest.TestCase):
def test_basic(self):
date1 = "2024-07-11 01:03:04"
date2 = "2021-01-01 02:01:01"
date1 = datetime.strptime(date1, "%Y-%m-%d %H:%M:%S")
date2 = datetime.strptime(date2, "%Y-%m-%d %H:%M:%S")
d = date1 - date2
print(d.total_seconds() / (24 * 60 * 60 * 365))
def test_sub_seconds(self):
date1 = "2024-07-11 01:03:04"
date2 = "2021-01-01 02:01:01"
print(ztime.calc.sub_seconds(date1, date2))
print(ztime.calc.sub_minutes(date1, date2))
print(ztime.calc.sub_hours(date1, date2))
print(ztime.calc.sub_days(date1, date2))
print(ztime.calc.sub_months(date1, date2))
print(ztime.calc.sub_years(date1, date2))
测试结果如下：
