C++实现童年游戏

 其中多处坐标的代码是经过运算移项推导出的

#include<easyx.h>
#include<conio.h>
#include<time.h>
#include<stdio.h>
bool Timer(int id, int ms)//计时器，过了多少毫秒就会返回真
{
	static long start[3] = { 0 };
	long last = clock();
	if (last - start[id] >= ms)
	{
		start[id] = last;
		return true;
	}
	else return false;
}
void fail()
{
	settextstyle(600, 0, 0);
	settextcolor(RED);
	outtextxy(800, 500, "你死了!");
	EndBatchDraw();
	_getch();
}
class Car {
public:
	short x, y;
	COLORREF color;
	void isHit(short objx, short objy)
	{
		if (!(x > objx + 65 || x + 65 < objx || 715 > objy || 885 < objy))
			fail();
	}

	void show()
	{
		setfillcolor(color);
		solidcircle(x + 10, y + 10, 10);
		solidcircle(x + 55, y + 10, 10);
		solidrectangle(x + 20, y + 20, x + 45, y + 65);
		solidcircle(x + 10, y + 75, 10);
		solidcircle(x + 55, y + 75, 10);//长度65，宽度85
	}

};

class Npc :public Car
{
public:
	bool isLive = false;
	static Npc* p;
	static int* a;
	bool overLap(int j)
	{
		for (int i = 0; i < 6; i++)
		{
			if (i == j || p[i].isLive == false)
				continue;
			if (!(x > p[i].x + 65 || x + 65 < p[i].x || 86 < p[i].y))
				return true;
		}
		return false;
	}
	static void loop(Car*player,int j) {
		for (int i = 0; i < 6; i++)
		{
			int c = 0;
			if (p[i].isLive == false && rand() % 100 == 0)
			{
				short n1 = a[j], n2 = a[j + 1 > 53 ? 0 : j + 1], n3 = a[j + 2 > 53 ? j - 52 : 2], length;
				short max = (n1 > n2 ? n1 : n2) > n3 ? (n1 > n2 ? n1 : n2) : n3;
				short min = (n1 < n2 ? n1 : n2) < n3 ? (n1 < n2 ? n1 : n2) : n3;
				length = min + 835 - max;//max-min+900-65，算出车辆x坐标可出现的变动值
				do { p[i].x = rand() % length + 10 + max; }//随机偏移量加上最右边的道路方块起始坐标
				while (p[i].overLap(i) && c++ < 1000);
				p[i].isLive = true;
				p[i].y = 1;
				p[i].color = RGB(rand() % 200 + 56, rand() % 200 + 56, rand() % 200 + 56);
			}
		}
		for (int i = 0; i < 6; i++)
		{
			if (p[i].isLive)
			{
				if (p[i].y >= 1080)
					p[i].isLive = false;
				p[i].y += 20;
				p[i].show();
				player->isHit(p[i].x, p[i].y);//判断有没有撞击敌机
			}
		}
	}
};
Npc* Npc::p = 0;
int* Npc::a = 0;
int main()
{
	short a[54] = { 0 };//道路两旁横坐标数组,为了生成蜿蜒曲折的路,用数组模拟双向循环链表
	short dire = 0, lastdire = 0, c = 0, t = 30, change = 0, behind = 0, j = 0, metre = 0;//c为道路绵延相同方向的次数
	ExMessage ex = { 0 }; bool mouseclick = 0; char str[128];
	Car player;
	player.x = 500, player.y = 800, player.color = RGB(0, 255, 255);
	Npc npc[6];
	Npc::p = npc;
	srand(time(0));
	//车路宽度为920
	initgraph(1920, 1080);
	setbkmode(TRANSPARENT);
	settextstyle(100, 0, 0);
	settextcolor(GREEN);
	_getch();
	while (1)
	{
		if (peekmessage(&ex, EX_MOUSE))//监听鼠标事件
		{
			switch (ex.message)
			{
			case WM_LBUTTONDOWN:
				if (ex.x > player.x && ex.x < player.x + 45)
					mouseclick = 1;
				break;
			case WM_LBUTTONUP:
				mouseclick = 0;
			}
			if (mouseclick)//只有拖拽不放才能移动，不能单击任意位置实现瞬移
				player.x = ex.x - 22;
		}
		if (Timer(1, 3000) && t > 5)
			t--;
		if (Timer(2, t * 4))
		{
			metre++;
			sprintf_s(str, "%d米", metre);
		}
		if (Timer(0, t))
		{
			BeginBatchDraw();
			cleardevice();
			int color = 255;
			for (int i = 0; i < 54; i++)
			{
				int index, x;
				if (j + i > 53)
					index = j + i - 54;
				else index = j + i;
				x = a[index];
				setfillcolor(RGB(color, color, 0));
				color -= 4;//道路颜色变淡
				solidrectangle(x, i * 20 + 1, x + 10, i * 20 + 21);
				x += 910;
				solidrectangle(x, i * 20 + 1, x + 10, i * 20 + 21);
			}
			player.show();
			Npc::loop(npc, j);
			for (int i = 3, y = 40 + j; i < 6; i++)//检测主角是否撞到道路
			{
				int index, x;
				if (y + i > 53)
					index = y + i - 54;
				else index = y + i;
				x = a[index];
				if (x + 10 > player.x || x + 865 < player.x)
					fail();
			}
			outtextxy(0, 0, str);
			if (j-- == -1)//j为道路最前面对应的数组下标,自减后是新一轮的下标
			{
				behind = 0;
				j = 53;
			}
			else behind = j + 1;
			if (c >= 13)
				dire = rand() % 3 - 1;
			if (dire == lastdire)
				c++;
			else c = 1;
			lastdire = dire;
			change = dire * 2 * (rand() % 4 + 1);
			int tmp = a[behind] + change;
			if (tmp > 0 && tmp <= 1000)
				a[j] = tmp;
			else a[j] = a[behind];
			//前面的路受后面影响							
			EndBatchDraw();
		}
	}
}