牛客小白月赛88

E.多重映射

解题思路

• 对集合进行整体操作，集合大小只增不减，问最后集合标号
• 维护集合，考虑并查集
• 但直接用并差集维护会有以下问题：
• 当前集合变标号，可能会和之前标号相同，则进行并查集操作时，会接上之前的变换
• 为消除其影响，考虑加入时间戳，后面新产生的标号与之前的不同
• 进行操作时，若没有则跳过
• 若没有，则产生新的集合，对应的时间戳
• 若有，则合并集合，时间戳不变
• 
• 时，带上时间戳

import java.io.*;
import java.math.BigInteger;
import java.util.Arrays;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Objects;
import java.util.PriorityQueue;
import java.util.Stack;
import java.util.StringTokenizer;








//implements Runnable
public class Main{
	static long md=(long)998244353;
	static long Linf=Long.MAX_VALUE/2;
	static int inf=Integer.MAX_VALUE/2;
	static int N=2000000;
	static int n=0;
	static int m=0;
	
	static 
	class Node{
		int x;
		int y;
		public Node(int u,int v) {
			x=u;
			y=v;
		}
		@Override
	    public boolean equals(Object o) {
	        if (this == o) return true;
	        if (o == null || getClass() != o.getClass()) return false;
	        Node may = (Node) o;
	        return x == may.x && y==may.y;
	    }

	    @Override
	    public int hashCode() {
	        return Objects.hash(x, y);
	    }
	}
	static HashMap<Node, Node> fa=new HashMap<Node, Node>();
	static Node find(Node x) {//跟正常并查集一样
		if(x.x==fa.get(x).x&&x.y==fa.get(x).y)return x;
		else {
			Node f=fa.get(x);
			Node ff=find(f);
			fa.put(f, ff);
			return ff;
		}
	}
	static int[] a=new int[N+1];
	static int[] x=new int[N+1];
	static int[] y=new int[N+1];
	static boolean[] hs=new boolean[N+1];
	static int[] t=new int[N+1];
	public static void main(String[] args) throws Exception{
		AReader input=new AReader();
		PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));	
		int T=input.nextInt();
		while(T>0) {
			n=input.nextInt();
			m=input.nextInt();
			
			for(int i=1;i<=n;++i) {
				a[i]=input.nextInt();
                Node ro=new Node(a[i], 0);
				fa.put(ro, ro);//初始化，重复添无影响
				hs[a[i]]=true;
			}
			
			for(int i=1;i<=m;++i) {
				x[i]=input.nextInt();
				y[i]=input.nextInt();
				Node lo=new Node(x[i], 0);
				Node ro=new Node(y[i], 0);
                fa.put(lo, lo);
                fa.put(ro, ro);//初始化，重复添无影响
			}
//			out.print(fa.get(new Node(1, 0)));
			for(int i=1;i<=m;++i) {
				int l=x[i];
				int r=y[i];
				if(!hs[l])continue;
				
				if(!hs[r]) {//与之前区别
					t[r]++;
				}
                hs[l]=false;
				hs[r]=true;
				Node lo=new Node(l, t[l]);
				Node ro=new Node(r, t[r]);
				fa.put(lo, ro);
//				out.print(fa.get(ro));
				fa.put(ro, ro);//集合头自己指自己，初始化，重复添无影响
			}
			
//			out.print(fa.get(new Node(1, 0)));
			for(int i=1;i<=n;++i) {
				Node fx=find(new Node(a[i], 0));
				out.print(fx.x+" ");
			}
		    out.println();
            //清空
		    for(int i=1;i<=n;++i) {
		    	hs[a[i]]=false;
		    	t[a[i]]=0;
		    }
		    for(int i=1;i<=m;++i) {
		    	hs[x[i]]=false;
		    	t[x[i]]=0;
		    	hs[y[i]]=false;
		    	t[y[i]]=0;
		    }
            fa.clear();
			T--;
		}
	    out.flush();
	    out.close();
	}
//	public static final void main(String[] args) throws Exception {
//		  new Thread(null, new Main(), "线程名字", 1 << 27).start();
//	}
//		@Override
//		public void run() {
//			try {
//				//原本main函数的内容
//				solve();
//
//			} catch (Exception e) {
//			}
//		}
		static
		class AReader{ 
		    BufferedReader bf;
		    StringTokenizer st;
		    BufferedWriter bw;

		    public AReader(){
		        bf=new BufferedReader(new InputStreamReader(System.in));
		        st=new StringTokenizer("");
		        bw=new BufferedWriter(new OutputStreamWriter(System.out));
		    }
		    public String nextLine() throws IOException{
		        return bf.readLine();
		    }
		    public String next() throws IOException{
		        while(!st.hasMoreTokens()){
		            st=new StringTokenizer(bf.readLine());
		        }
		        return st.nextToken();
		    }
		    public char nextChar() throws IOException{
		        //确定下一个token只有一个字符的时候再用
		        return next().charAt(0);
		    }
		    public int nextInt() throws IOException{
		        return Integer.parseInt(next());
		    }
		    public long nextLong() throws IOException{
		        return Long.parseLong(next());
		    }
		    public double nextDouble() throws IOException{
		        return Double.parseDouble(next());
		    }
		    public float nextFloat() throws IOException{
		        return Float.parseFloat(next());
		    }
		    public byte nextByte() throws IOException{
		        return Byte.parseByte(next());
		    }
		    public short nextShort() throws IOException{
		        return Short.parseShort(next());
		    }
		    public BigInteger nextBigInteger() throws IOException{
		        return new BigInteger(next());
		    }
		    public void println() throws IOException {
		        bw.newLine();
		    }
		    public void println(int[] arr) throws IOException{
		        for (int value : arr) {
		            bw.write(value + " ");
		        }
		        println();
		    }
		    public void println(int l, int r, int[] arr) throws IOException{
		        for (int i = l; i <= r; i ++) {
		            bw.write(arr[i] + " ");
		        }
		        println();
		    }
		    public void println(int a) throws IOException{
		        bw.write(String.valueOf(a));
		        bw.newLine();
		    }
		    public void print(int a) throws IOException{
		        bw.write(String.valueOf(a));
		    }
		    public void println(String a) throws IOException{
		        bw.write(a);
		        bw.newLine();
		    }
		    public void print(String a) throws IOException{
		        bw.write(a);
		    }
		    public void println(long a) throws IOException{
		        bw.write(String.valueOf(a));
		        bw.newLine();
		    }
		    public void print(long a) throws IOException{
		        bw.write(String.valueOf(a));
		    }
		    public void println(double a) throws IOException{
		        bw.write(String.valueOf(a));
		        bw.newLine();
		    }
		    public void print(double a) throws IOException{
		        bw.write(String.valueOf(a));
		    }
		    public void print(char a) throws IOException{
		        bw.write(String.valueOf(a));
		    }
		    public void println(char a) throws IOException{
		        bw.write(String.valueOf(a));
		        bw.newLine();
		    }
		}
	}