1.题目描述
2.解题思路
刚看到这个题目的时候，感觉说的有点啰嗦，其实不难发现，这个题目和之前的给你多少钱，什么2元，5元的，给你一个数字，让你算各种钱币有多少张。无非就是从小到大进行判断，首先判断给定的数字，能容纳多少个最大的，然后依次减少。
3.代码实现
class Solution:
def intToRoman(self, num: int) -> str:
str1 = ""
while num != 0:
print("num",num)
if int(num / 1000):
num1 = int(num / 1000)
for i in range(0, num1):
str1 = str1 + "M"
num = num - num1 * 1000
elif int(num / 900):
num1 = int(num / 900)
for i in range(0, num1):
str1 = str1 + "CM"
num = num - num1 * 900
elif int(num / 500):
num1 = int(num / 500)
for i in range(0, num1):
str1 = str1 + "D"
num = num - num1 * 500
elif int(num / 400):
num1 = int(num / 400)
for i in range(0, num1):
str1 = str1 + "CD"
num = num - num1 * 400
elif int(num / 100):
num1 = int(num / 100)
for i in range(0, num1):
str1 = str1 + "C"
num = num - num1 * 100
elif int(num / 90):
num1 = int(num / 90)
for i in range(0, num1):
str1 = str1 + "XC"
num = num - num1 * 90
elif int(num / 50):
num1 = int(num / 50)
for i in range(0, num1):
str1 = str1 + "L"
num = num - num1 * 50
elif int(num / 40):
num1 = int(num / 40)
for i in range(0, num1):
str1 = str1 + "XL"
num = num - num1 * 40
elif int(num / 10):
num1 = int(num / 10)
for i in range(0, num1):
str1 = str1 + "X"
num = num - num1 * 10
elif int(num / 9):
num1 = int(num / 9)
for i in range(0, num1):
str1 = str1 + "IX"
num = num - num1 * 9
elif int(num / 5):
num1 = int(num / 5)
for i in range(0, num1):
str1 = str1 + "V"
num = num - num1 * 5
elif int(num / 4):
num1 = int(num / 4)
for i in range(0, num1):
str1 = str1 + "IV"
num = num - num1 * 4
elif int(num / 1):
num1 = int(num / 1)
for i in range(0, num1):
str1 = str1 + "I"
num = num - num1 * 1
return str1
